[mythtv-users] Will autoexpire auto-re-record?
Derek Battams
derek at battams.ca
Wed Feb 22 05:26:55 UTC 2006
Quoting Mike Grusin <mgrusin at comcast.net>:
> Quick question: if a program autoexpires before you get a chance to watch
> it, is Myth supposed to automatically re-record it when it appears in the
> schedule again?
>
> I had previously thought it was supposed to do this, but I've just run into
> a few situations where it clearly didn't (the olympics have pushed a lot of
> stuff off my system ;) I'm still on 18.1.
>
> Thanks! -Mike G.
I plan on investigating this exact issue relatively soon, but this
seems like a good time to start the discussion. ;-)
My understanding of how this works (from an initial investigation a
long, long time ago) is that if Myth auto expires a recording and you
have set the 'RerecordAutoExpired' option to on it will remove it from
the oldrecorded table of the database, which allows that program to be
recorded again, in theory. However, if the recording rule used to
record the show is set to only record new episodes then by the time the
booted recording airs again it won't likely be considered a new episode
and therefore won't be recorded again. This is how I saw it working
when I first looked at this back on 0.18. It may not work like that on
0.19 (haven't looked yet) plus the first time I looked at this was when
I was relatively new to MythTV so my findings may not have even been
correct.
If I was correct and it hasn't changed in 0.19 then my proposed
solution would be to create a 'Find Once' recording rule using the
programid of the show with a priority of one higher than that of the
originating rule. With this you'll then be assurred of re-recording
the booted program when it next reairs.
I remember investigating this originally because something like this
happened to me shortly after installing MythTV, but hasn't happened
since. I came across my notes about it a week or so ago and thought it
might be worth investigating it and implementing my solution if it does
indeed work the way I orginally found it to. I'm sure someone will
correct me if my understanding of this is incorrect. ;-)
- Derek
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