<div class="gmail_quote">On Dec 21, 2007 7:50 PM, Scott Pleavin <<a href="mailto:scott.pleavin@rogers.com">scott.pleavin@rogers.com</a>> wrote:<br>
<blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">Would you need the same resistor and capacitor on a S/PDIF input?<br><font color="#888888"><br>Scott<br></font>
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<div class="Wj3C7c"><br>Adilson Oliveira wrote:<br>> -----BEGIN PGP SIGNED MESSAGE-----<br>> Hash: SHA1<br>><br>> Willy Boyd escreveu:<br>><br>>> On Dec 20, 2007 2:56 PM, Sean Goodpasture <<a href="mailto:goofygrin@gmail.com">
goofygrin@gmail.com</a>> wrote:<br>>><br>>>> I'd have to take apart my main front end... Maybe this weekend. I'm using<br>>>> it with the asus M2NPV and it's not nearly as complicated as what the other
<br>>>> David posted...<br>>>><br>>> So you just wired it straight up? No resistors or capacitors needed?<br>>> Because I have the same motherboard. Sounds like a simple little hack<br>>> to attempt this weekend.
<br>>><br>><br>> You *do* need a resistor and capacitor. If you wire in directly, it<br>> might work but the resistor helps adjusting the impedance and the<br>> capacitor provides a DC isolation. I failed to do that once (I have the
<br>> same MB) and almost burned my receiver.<br>> A simple circuit like this is enough.<br>><br>> 100nF<br>> TTL ----||-----330ohm--+--------- coax S/PDIF signal out<br>> in |
<br>> 100ohm<br>> |<br>> Ground -----------------+--------- coax signal ground<br>><br>><br>> []s<br>><br>> Adilson.<br>> -----BEGIN PGP SIGNATURE-----
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http://mythtv.org/cgi-bin/mailman/listinfo/mythtv-users</a><br><br></blockquote></div><br>COAX and SPDIF are the same thing. Optical is the same data over a different transmission method.