[mythtv] LastFM support in MythMusic

[Willem Ligtenberg]

OK, well with the malloc in place, it now actually works.
I do not have a vector implementation, yet...
But I do know the encoding that should be used, namely utf8, I already
know how to convert the QString to utf8, so that is no problem.
But the thing I really want is a hexadecimal representation of that
binary data and cast that to a string, just like the normal md5sum
would do.
Any ideas on how to accomplish that?
I know casting won't work :)

Thanks,

Willem

On Tue, Feb 26, 2008 at 7:32 PM, Anduin Withers <awithers at anduin.com> wrote:
> > I have created an extra method:
>  > uint8_t *my_md5(QString string)
>  > {
>  >     uint8_t *md5val;
>  >     uint8_t *c_string = (uint8_t*)string.toUInt();
>  >     av_md5_sum(md5val, c_string, string.length());
>  >     return md5val;
>  > }
>  > [...]
>  > cout << *test << endl;
>
>  You probably do not want to do that, it will output only the first byte, you
>  definitely do not want to "cout << test", the returned data is 16 bytes of
>  binary data, there is no null termination (and would be gibberish anyway).
>
>  Personally I'd return a std::vector<uint8_t>, you incur the tremendous cost
>  of a copy but you don't need to remember to free()/delete.
>
>  std::vector<uint8_t> my_md5(const QString &s)
>  {
>     std::vector<uint8_t> md5val(16);
>     QCString cs = s.utf8();
>     av_md5_sum(&md5val[0], reinterpret_cast<const uint8_t *>(cs.data()),
>                cs.length());
>     return md5val;
>  }
>
>  You should spend some time thinking about the encoding of the string. If you
>  are comparing you need to ensure both sources agree on the encoding before
>  the digest is generated.
>
>  --
>  Anduin Withers
>
>
>
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